What is the sum of the first 70 consecutive odd numbers?

1 through 2*70 - 1 or 139 figure that out by experiment

average = (1+139)/2 = 70

70 * 70 = 4900

By the way

what we really did was :

n[(n*2-1)+1 ]/2

which is n^2

or 70^2

Well, let me put on my thinking cap, or rather, my clown nose, and do some math for you.

The first odd number is 1, and the second odd number is 3. We can notice that each odd number is 2 more than the previous odd number.

So, let's find the 70th consecutive odd number. We know that it is 2 more than the 69th odd number, which is 2 more than the 68th odd number, and so on.

So, if we add up all these odd numbers from 1 to 69, we get a sum that represents the total sum of the first 69 consecutive odd numbers.

Now, let's find the 70th odd number. We know that it is 2 more than the 69th odd number, so we simply add 2 to that sum we calculated earlier.

Now, if my clown calculator is working properly, the sum of the first 70 consecutive odd numbers should be the sum of the first 69 odd numbers plus 2.

And the answer is... I'm sorry, I seem to have misplaced my answer card. Oh no, it's right here! *pulls out a card* The sum is 4,900.

So, the sum of the first 70 consecutive odd numbers is 4,900.

To find the sum of the first 70 consecutive odd numbers, first, we need to determine the formula for finding the nth odd number. The formula for the nth odd number is 2n - 1, where n is the position of the odd number.

Now, let's find the sum by following these steps:

Step 1: Find the first odd number
To find the first odd number, substitute n = 1 into the formula:
2(1) - 1 = 1

Therefore, the first odd number is 1.

Step 2: Find the last odd number
To find the last odd number, substitute n = 70 into the formula:
2(70) - 1 = 139

Therefore, the last odd number is 139.

Step 3: Find the sum of the first and last odd numbers
Sum = first odd number + last odd number
Sum = 1 + 139
Sum = 140

Therefore, the sum of the first 70 consecutive odd numbers is 140.

To find the sum of consecutive odd numbers, we can use a formula: the sum of the first n odd numbers is n^2. In this case, we want to find the sum of the first 70 consecutive odd numbers.

So, we need to find the square of 70, which is 70^2.

To calculate this, multiply 70 by itself:

70^2 = 70 * 70 = 4900.

Therefore, the sum of the first 70 consecutive odd numbers is 4900.