A TRAIN LEAVES THE STATION AT THE 0.0 M MARKER TRAVELING WITH A CONSTANT VELOCITY OF 36.0 M/S.

A) WHAT IS THE VELOCITY OF THE TRAIN IN KM/HR.

This is an exercise in converting from one speed unit (m/s) to another (km/h). You should learn the "factor label" method. It works like this.

36.0 m/s*(1 km/1000m)*(3600s/h)
= 129.6 km/h

Well, let's do some math here! To convert meters per second to kilometers per hour, we need to multiply the velocity by a conversion factor. There are 1000 meters in a kilometer and 3600 seconds in an hour. So, the formula is:

Velocity (km/hr) = Velocity (m/s) * (3600 s/1 hr) * (1 km/1000 m)

Plugging in the values:
Velocity (km/hr) = 36.0 m/s * (3600 s/1 hr) * (1 km/1000 m)

After crunching the numbers, the velocity of the train is approximately 129.6 km/hr. That's one speedy train! Just make sure you don't blink, or you might miss it!

To convert the velocity of the train from m/s to km/hr, you can use the conversion factor:

1 km = 1000 m
1 hr = 3600 s

First, we'll convert the velocity from m/s to km/s by dividing by 1000.
36.0 m/s ÷ 1000 = 0.036 km/s

Next, we'll convert km/s to km/hr by multiplying by 3600.
0.036 km/s × 3600 = 129.6 km/hr

Therefore, the velocity of the train is 129.6 km/hr.

To find the velocity of the train in km/hr, we need to convert the velocity from m/s to km/hr.

Step 1: Convert m/s to km/s.
To convert from m/s to km/s, divide the velocity in m/s by 1000 (since there are 1000 meters in a kilometer).

36.0 m/s ÷ 1000 = 0.036 km/s

Step 2: Convert km/s to km/hr.
To convert from km/s to km/hr, multiply the velocity in km/s by 3600 (since there are 3600 seconds in an hour).

0.036 km/s × 3600 = 129.6 km/hr

Therefore, the velocity of the train is 129.6 km/hr.