Using Coulomb's Law, calculate the force of repulsion between a positive
charge of 110 Coulombs and another positive charge of 220 coulombs
separated by a distance of 2 meters. Use scientific notation.
(Hint: use the proportionality constant)
F = k Q1*Q2/R^2
k = 8.99*10^9
N*m^2/C^2 is the Coulomb constant
Solve for F in newtons
To calculate the force of repulsion between two charges using Coulomb's Law, we can use the following formula:
F = k * (q1 * q2) / r^2
Where:
- F is the force of repulsion
- k is the proportionality constant
- q1 and q2 are the magnitudes of the charges
- r is the distance between the charges
The proportionality constant, k, is defined as:
k = 9 * 10^9 N m^2 / C^2
Now, let's plug in the given values into the formula:
q1 = 110 C (positive charge)
q2 = 220 C (positive charge)
r = 2 m (distance between the charges)
k = 9 * 10^9 N m^2 / C^2
Substituting these values into the formula, we get:
F = (9 * 10^9 N m^2 / C^2) * (110 C * 220 C) / (2 m)^2
Simplifying further:
F = (9 * 10^9 N m^2 / C^2) * 24200 C^2 / 4 m^2
F = (9 * 10^9 N m^2 / C^2) * 6050
F = 5.445 * 10^13 N
Therefore, the force of repulsion between the two charges is 5.445 * 10^13 Newtons.