In order to reduce potential danger to the environment, a biohazard laboratory maintains an internal air pressure that is 1% lower than atmospheric pressure. The net force acting on a 1.8-m2 external window of this laboratory due to air pressure is most nearly
1.8 N
18 N
1.8 × 102 N
1.8 × 103 N
1.8 × 104 N
I thought I would just find 1% of atmospheric pressure and this was 1013 (atmospheric pressure is 101300 Pa). From using the P=F/A equation I think the answer is either 1.8e3 or 1.8e4... Can someone help me to ensure my calculations to reach my answer?
101325/100=1013 Pa,
1013•1.8 =1.8•10^3 N
To find the net force acting on the external window due to air pressure, you need to calculate the pressure difference between the inside and outside, and then multiply it by the area of the window.
Given that the internal air pressure is 1% lower than atmospheric pressure, you can find the pressure inside the laboratory as follows:
Internal pressure = Atmospheric pressure - (1% of Atmospheric pressure)
= 101300 Pa - (0.01 * 101300 Pa)
= 101300 Pa - 1013 Pa
= 100287 Pa
The pressure difference is the difference between the atmospheric pressure and the internal pressure:
Pressure difference = Atmospheric pressure - Internal pressure
= 101300 Pa - 100287 Pa
= 1013 Pa
Now, you can calculate the net force by multiplying the pressure difference by the area of the window:
Net force = Pressure difference * Area of the window
= 1013 Pa * 1.8 m²
= 1823.4 N
Therefore, the net force acting on the window is approximately 1823.4 N. Since none of the provided answer options match this exact value, it seems that there might be a rounding error or approximation in the available choices.
To find the net force acting on the window due to air pressure, we need to calculate the pressure difference between the inside and outside of the laboratory.
Given that the internal air pressure is 1% lower than atmospheric pressure, we can calculate the pressure inside the lab:
Pressure inside the lab = Atmospheric pressure - 1% of atmospheric pressure
= 101300 Pa - (1/100) * 101300 Pa
= 101300 Pa - 1013 Pa
= 100287 Pa
Now, using the formula P = F/A, we can rearrange it to solve for force:
Force = Pressure difference * Area
The pressure difference is the difference between atmospheric pressure outside and the pressure inside the lab, which is 101300 - 100287 Pa.
The area of the window is given as 1.8 m².
Let's substitute these values to calculate the force:
Force = (101300 - 100287 Pa) * 1.8 m²
= 1013 Pa * 1.8 m²
= 1823.4 N
Thus, the net force acting on the window due to air pressure is approximately 1823.4 N.
Given the answer choices provided, the closest option is 1.8 × 10³ N, which corresponds to 1.8 × 1000 N or 1800 N.