Two balls undergo inelastic collision. The y-momentum after the collision is 98 kilogram meters/second, and the x-momentum after the collision is 100 kilogram meters/second. What is the magnitude of the resultant momentum after the collision?

p=sqrt{p(x)² +p(y)²} =

= sqrt(98² +100²)=140 kg•m/s

v = Sqrt(v1^2 + v2^2)

v = sqrt(98^2 + 100^2)
V = 140.01
V = 1.4 * 10^2

To find the magnitude of the resultant momentum after the collision, we can use the Pythagorean theorem.

Let's denote the magnitude of the resultant momentum as R, the x-momentum as Px, and the y-momentum as Py.

Given:
Px = 100 kg·m/s
Py = 98 kg·m/s

Using the Pythagorean theorem, we have:
R^2 = Px^2 + Py^2

Substituting the given values, we get:
R^2 = (100 kg·m/s)^2 + (98 kg·m/s)^2

Calculating the square of each term:
R^2 = 10000 kg^2·m^2/s^2 + 9604 kg^2·m^2/s^2
R^2 = 19604 kg^2·m^2/s^2

Taking the square root of both sides:
R = √(19604 kg^2·m^2/s^2)

Simplifying:
R = 140 kg·m/s

Therefore, the magnitude of the resultant momentum after the collision is 140 kilogram meters/second.

To find the magnitude of the resultant momentum after the collision, we can use the Pythagorean theorem since we have the y-momentum and x-momentum.

The Pythagorean theorem states that the square of the magnitude of a vector (in this case, momentum) is equal to the sum of the squares of its components. Mathematically, it can be expressed as:

Magnitude^2 = y-momentum^2 + x-momentum^2

Plugging in the given values:

Magnitude^2 = 98^2 + 100^2

Magnitude^2 = 9604 + 10000

Magnitude^2 = 19604

To find the magnitude, we take the square root of both sides:

Magnitude = √19604

By evaluating the square root of 19604, we find:

Magnitude ≈ 139.95 kilogram meters/second

Therefore, the magnitude of the resultant momentum after the collision is approximately 139.95 kilogram meters/second.