Harry is twice as old as Doyle. Doyle's age is x years. Write in terms of x. A. Harry's age is 5 years ago. B. Doyle's age is 5 years ago. C. Find Doyle's age now if Harry's age was three times Doyle's age five years ago.
Doyle = x
Harry = 2x
Harry five years ago = 2x-5
Doyle five years ago = x-5
2x-5 = 3(x-5) = 3 x - 15
x = 10
Answer is correct
You have done right
A. Harry's age is 2x years.
B. Doyle's age is x years.
C. To find Doyle's age now, we need further information.
To write the expressions in terms of x, let's use the given information:
1. Harry is twice as old as Doyle.
- Since Doyle's age is x, Harry's age would be 2x.
Now, let's answer each part of the question:
A. Harry's age is 5 years ago.
- To express Harry's age 5 years ago, we subtract 5 from his current age: 2x - 5.
B. Doyle's age is 5 years ago.
- To express Doyle's age 5 years ago, we subtract 5 from his current age: x - 5.
C. Find Doyle's age now if Harry's age was three times Doyle's age five years ago.
- Five years ago, Harry's age was 2x - 5, and Doyle's age was x - 5.
- According to the information, Harry's age was three times Doyle's age.
So, we can set up the equation: 2x - 5 = 3(x - 5).
- Now, let's solve the equation for Doyle's age:
2x - 5 = 3x - 15
Subtract 2x from both sides:
-5 = x - 15
Add 15 to both sides:
10 = x
Therefore, Doyle's age now is 10 years old.