What volume of water should be added to 500 mL of a 1.0 mol/L CuSO4 solution to dilute it to 0.5 mol/L?
500 mL
To determine the volume of water needed to dilute a solution, we can use the formula for dilution:
C1V1 = C2V2,
where C1 and V1 are the initial concentration and volume, respectively, and C2 and V2 are the final concentration and volume, respectively.
In this case, we know the initial concentration (C1) is 1.0 mol/L, the initial volume (V1) is 500 mL, the final concentration (C2) is 0.5 mol/L, and we need to find the final volume (V2) of the solution after dilution.
Let's rearrange the formula to solve for V2:
V2 = (C1 * V1) / C2
Substituting the known values:
V2 = (1.0 mol/L * 500 mL) / 0.5 mol/L
Simplifying the equation:
V2 = 1000 mL
Therefore, you would need to add 1000 mL (or 1 liter) of water to the 500 mL of the 1.0 mol/L CuSO4 solution to dilute it to a 0.5 mol/L concentration.
To dilute the 1.0 mol/L CuSO4 solution to 0.5 mol/L, we need to calculate the volume of water that should be added.
We can use the dilution formula:
C1V1 = C2V2
where:
C1 = initial concentration
V1 = initial volume
C2 = final concentration
V2 = final volume
Plugging in the given values:
C1 = 1.0 mol/L
V1 = 500 mL = 0.5 L
C2 = 0.5 mol/L
V2 = unknown
The equation becomes:
(1.0 mol/L) * (0.5 L) = (0.5 mol/L) * (V2)
0.5 = 0.5V2
To isolate V2, divide both sides of the equation by 0.5:
V2 = 0.5 / 0.5 = 1 L
Therefore, you need to add 1 liter (1000 mL) of water to the 500 mL of the 1.0 mol/L CuSO4 solution to obtain a final concentration of 0.5 mol/L.