if a stone at the end of a string is whirled in a circle, the inward pull on the stone
A) is known as the centrifugal force
B) is inversely proportional to the speed of the object
C) is inversely proportional to the square of the speed
D) is proportional to the speed
E) is proportional to the square of the speed
plzz help me soon
A) is known as the centrifugal force
E) is proportional to the square of the speed
is propotional to the square of speed
as we know that
fc=mv^2/r
proportional to the speed
To determine the correct answer, we need to understand the concept of circular motion and the forces acting on an object in that motion.
When a stone is whirled in a circle at the end of a string, it experiences a force pulling it towards the center of the circle. This force is known as the centripetal force. The direction of the centripetal force is inward, towards the center of the circular path.
Now let's analyze the provided options:
A) The centripetal force is the force pulling the stone inward, not centrifugal force. So, option A is incorrect.
B) The centripetal force is not inversely proportional to the speed of the object. The centripetal force is actually directly proportional to the speed squared. So, option B is incorrect.
C) The centripetal force is directly proportional to the speed squared, not inversely proportional. Therefore, option C is incorrect.
D) The centripetal force is proportional to the speed squared, not directly proportional to the speed. So, option D is incorrect.
E) The centripetal force is indeed proportional to the square of the speed. As the speed of the object moving in a circular path increases, the centripetal force required to keep it in that path also increases. Hence, option E is correct.
Therefore, the correct answer is E) The inward pull on the stone is proportional to the square of the speed.