how far can a cyclist travel in 2.5 hrs along a straight road if her average speed is 18 km. per hr?

(ignore the actual question, what my teacher wants me to do is find the average speed and average velocity using these measurements.)
any help is greatly appreciated! :)
THANKS

thankyou :)

2.5 times 18 is the total distance traveled.

As you ordered, I am ignoring the velocity vector and positions on the x axis (displacement). If the person spent half the time going east and half the time going west all at constant speed, the net result would be lots of distance traveled but no change in location :)

Well, if the cyclist's average speed is 18 km per hour, we can simply multiply that speed by the amount of time to find the distance traveled. So, in 2.5 hours, the cyclist will have traveled... wait for it... 45 kilometers! Just make sure the cyclist doesn't take any detours to the circus along the way!

To find the distance traveled by the cyclist in 2.5 hours, you can use the formula: distance = speed × time.

The average speed of the cyclist is given as 18 km/hr, and the time is 2.5 hours. Plugging these values into the formula, we get:

distance = 18 km/hr × 2.5 hrs = 45 km

Therefore, the cyclist can travel a distance of 45 kilometers along a straight road in 2.5 hours.

Now, let's quickly explain how to find average speed and average velocity using these measurements:

Average speed is the total distance traveled divided by the total time taken. In this case, the total distance is 45 km, and the total time is 2.5 hours. So, the average speed is:

average speed = total distance / total time = 45 km / 2.5 hrs = 18 km/hr

Average velocity, on the other hand, takes into account the displacement (change in position) and the direction. In this case, since the cyclist is traveling along a straight road, the displacement is simply the distance traveled. Therefore, the average velocity would also be 18 km/hr, considering there is no change in direction.