a satellite completes one revolution of a planet in almost exactly one hour. at the end of an hour , the satellite has traveled 2.0x10^7 meters and is only 10 meters away from its starting point. What is the numerical value of the satellite's average velocity after that one hour?
The trick here is to recognize that they are asking for average velocity, not speed. In exactly one hour, it is only 10 meters from where is was 3600 seconds ago. Compute the ratio, 10 m/3600 s
To find the average velocity of the satellite, we divide the total displacement by the total time taken. In this case, the displacement is the distance between the starting point and the ending point, and the time is given as one hour.
Displacement = 10 meters
Time = 1 hour = 3600 seconds
Average Velocity = Displacement / Time
Substituting the values, we get:
Average Velocity = 10 meters / 3600 seconds
To simplify this, we can convert the time from seconds to hours:
Average Velocity = 10 meters / 3600 seconds * (1 hour / 3600 seconds)
Now, we can multiply the numerator and denominator by the same value so that the units cancel out appropriately:
Average Velocity = 10 meters * (1 hour / 3600 seconds) / 3600 seconds * (1 hour / 3600 seconds)
Simplifying further, we have:
Average Velocity = (10 meters / 3600 seconds^2) * (1 hour / 3600 seconds)
Average Velocity = 10 meters / 3600 seconds^2 * hour
Finally, to get the numerical value of the average velocity, we need to calculate it using the given values:
Average Velocity = 10 meters / (3600^2) * hour
Calculating this will give us the numerical value of the satellite's average velocity after one hour.