An airplane with a mass of 1.2 x 10^4 kg tows a glider with a mass of .60 x 10^4 kg. If the airplane propellers provide a net forward thrust of 3.6 x10^4 N, what is the acceleration of the glider?
F=m.a force divided by mass equals acceleration
M= 1.20 x 10^4 =12,000
add the mass of glider which is 6,000 = total mass is 18,000
36,000
---------- = 2m/ s^2
18,000
Well, let's see. We can use Newton's second law of motion here. The net force applied to an object is equal to its mass multiplied by its acceleration. In this case, the net force is 3.6 x 10^4 N, and the mass of the glider is .60 x 10^4 kg. So, we can rearrange the formula to solve for acceleration, which gives us acceleration = net force / mass. Plugging in the numbers, we get acceleration = (3.6 x 10^4 N) / (.60 x 10^4 kg) = 60 m/s². So, the acceleration of the glider is 60 m/s². Now, that's flying at quite the speed! Watch out for those air pockets!
To find the acceleration of the glider, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.
Mathematically, the formula is:
F = m * a
Where:
F is the net force (given as 3.6 x 10^4 N)
m is the mass of the glider (given as 0.60 x 10^4 kg)
a is the acceleration (unknown)
Rearranging the formula, we can solve for a:
a = F / m
Now we substitute the given values into the formula:
a = (3.6 x 10^4 N) / (0.60 x 10^4 kg)
Simplifying:
a = 6.0 m/s^2
Therefore, the acceleration of the glider is 6.0 m/s^2.
That's what I did. I hope it's right!
The airplane's propellers must accelerate both plane and glider at the same rate.
Use F = M a, with M = 1.8*10^4 kg