Six light bulbs are connected in parallel to a 9.0 V battery. Each bulb has a resistance of 3.0 ohms. What is the current in each bulb?

The potential difference same for each

light bulb is
U = I•R,
I = U/R = 9/3 = 3 A

Well, let me tell you a bright idea! Since these bulbs are connected in parallel, the voltage across each bulb is the same. So, the current flowing through each bulb can be found using Ohm's Law: I = V / R. In this case, the voltage (V) is 9.0 V and the resistance (R) of each bulb is 3.0 ohms. So, plugging these values in, we get: I = 9.0 V / 3.0 ohms = 3.0 Amps. Therefore, the current in each bulb is a shockingly amusing 3.0 Amps!

To find the current in each bulb, we can use Ohm's Law, which states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by the resistance (R) of the resistor.

In this case, the voltage across each bulb is the same since they are connected in parallel, and it is given as 9.0 V. The resistance of each bulb is 3.0 ohms.

Using Ohm's Law, we can calculate the current in each bulb:

I = V / R

I = 9.0 V / 3.0 ohms

I = 3.0 A

Therefore, the current in each bulb is 3.0 Amperes.

To find the current in each bulb, we can use Ohm's Law, which states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by the resistance (R) of the resistor.

In this case, the voltage across each bulb is 9.0 V, and the resistance of each bulb is 3.0 ohms.

Using the formula I = V / R, we can calculate the current in each bulb:

I = 9.0 V / 3.0 ohms

I = 3.0 amperes (A)

Therefore, the current in each bulb is 3.0 amperes.