How many grams of NaOH must be dissolved in water to make 750ml of 1.7 M solution? (molecular weight of NaOH = 4Og/mol)

To calculate the number of grams of NaOH required to make a 1.7 M solution in 750 mL of water, you can follow these steps:

Step 1: Convert the volume from milliliters to liters:
750 mL = 750/1000 = 0.75 L

Step 2: Calculate the number of moles of NaOH needed using the Molarity formula:
Molarity (M) = Moles (mol)/ Volume (L)

Rearranging the formula:
Moles (mol) = Molarity (M) * Volume (L)

Moles (mol) = 1.7 M * 0.75 L

Step 3: Calculate the mass of NaOH using the formula: Moles (mol) * Molecular Weight (g/mol)
Molecular Weight of NaOH = 40 g/mol

Mass (g) = Moles (mol) * Molecular Weight (g/mol)
Mass (g) = (1.7 M * 0.75 L) * 40 g/mol

Mass (g) = 51 g

Therefore, you will need 51 grams of NaOH to make a 750 mL solution with a concentration of 1.7 M.

How many mols NaOH do you need? M x L = mols.

Then mols NaOH = grams/molar mass. You know mols and molar mass, solve for grams.