The probability that a house will develop a leak is 5%. If 20 house holds are randomly selected, what is the mean number if houses that developed leaks?

.05 *20 = ?

I thought that was it. It just seemed to easy. Thanks

% of the community favored having a pool in the new park. If citizens are chosen, find the probability that exactly of them favor the pool.

To find the mean number of houses that developed leaks, we can use the concept of expected value. The expected value is found by multiplying the probability of an event occurring by the number of times the event can occur.

In this case, the probability that a house will develop a leak is 5% or 0.05. So, for each house, the probability of it developing a leak is 0.05.

Now, we can consider the 20 randomly selected houses. Since the houses are randomly selected, the probability of each individual house developing a leak is independent of the others. Therefore, the number of houses that develop leaks follows a binomial distribution.

The mean number of houses that develop leaks can be calculated by multiplying the probability of each house developing a leak by the total number of houses. So, the mean number of houses that developed leaks would be:

Mean = Probability of leak x Number of houses

Mean = 0.05 x 20

Mean = 1

Therefore, the mean number of houses that developed leaks would be 1.