12. In a calorimeter, 10 g of ice absorbs heat with an enthalpy of fusion of 334 J/g. What is the heat absorbed?
q = mCHf
I am having a lot of trouble on this type of problem in chem. Help and an explanation would be greatly appreciated. Thank you.
When you are moving within a phase (for example, liquid water at one T to liquid water at another T OR ice at one T to ice at another T OR steam at one T to steam at another T), the equation to use is
q = mass x specific heat of the substance in that phase x (Tfinal-Tintial).
When you are at the phase change point (ice or liquid water at zero C) the formula is
q = mass x heat fusion. + if ice to liquid or - if liquid to solid.
When you are at the phase change point at the other end (liquid water or steam at 100 C) the formula is
q = mass x heat vaporization. + if liquid to steam or - if steam to liquid.
In the problem above it is
q = mass x heat fusion
q = 10 g x 334 J/g = 3340 J. Since the ice is absorbing heat it is + 334 J.
Thanks so much DrBob222. This helped a bunch!
Well, well, well, looks like chemistry is giving you the chills! But don't worry, I'm here to melt away your confusion.
To solve this problem, you need to use the equation:
q = mCHf
where q is the heat absorbed (in joules), m is the mass of the substance (in grams), and Hf is the enthalpy of fusion (in joules per gram).
In this case, you are given that the mass of ice (m) is 10 g, and the enthalpy of fusion (Hf) is 334 J/g.
Now, all you need to do is plug in the values and calculate! So, drumroll please...
q = (10 g) x (334 J/g)
Hold your breath...
q = 3340 J
And there you have it! The heat absorbed by the ice is 3340 joules. It's as easy as pie... err, ice!
To solve this problem, we can use the formula q = mCHf, where q represents the heat absorbed, m represents the mass of the substance, C represents the specific heat capacity, and Hf represents the enthalpy of fusion.
Given:
Mass of ice (m) = 10 g
Enthalpy of fusion (Hf) = 334 J/g
Using the given values, we can substitute them into the formula:
q = mCHf
q = (10 g)(334 J/g)
Next, we multiply the mass of the ice (10 g) by the enthalpy of fusion (334 J/g):
q = 3340 J
Therefore, the heat absorbed by the ice is 3340 J.
Sure! I'd be happy to help you with this chemistry problem.
To find the heat absorbed in this particular scenario, you need to use the formula q = mCHf, where q represents the heat absorbed, m is the mass of the substance (in grams), CHf is the enthalpy of fusion (also known as the heat of fusion) of the substance (in J/g).
In this problem, you are given that the mass of ice is 10 g and the enthalpy of fusion is 334 J/g.
To find the heat absorbed, simply plug these values into the formula:
q = 10 g x 334 J/g
Now, you need to perform the calculation:
q = 10 g x 334 J/g
q = 3340 J
So, the heat absorbed in this scenario is 3340 J.
Remember to pay attention to the units in your calculations, as they can greatly affect the final result. In this case, both the mass and the enthalpy of fusion were given in grams, so the answer will be in joules (J).
I hope this explanation helps you understand how to approach and solve similar problems in the future. If you have any further questions, feel free to ask!