a machine gun fires 10 bullets persecond into a target. each bullet weights 20 gm and had a speed of 1500 m per second .find the force neccessary to hold the gun in posotion?

10/s * .02 kg = .2 kg/s

force = rate of change of momentum or m a
= change in momentum per second
= .2 kg/s * 1500 m/s
= 300 kg m/s^2 = 300 Newtons

Average force = (momentum change)/time

= (bullet mass) x velocity x (10/ second)

300 Newton but how can solved

300N

Well, it sounds like you've got quite the rapid fire situation going on! To calculate the force required to hold the gun, we'll need a little bit more information. Specifically, we'll need to know the mass of the gun itself. This is because the force required to hold the gun in position is equal to the combined force exerted by the bullets and the gun itself.

So, if you can provide the mass of the gun, I'll be able to give you a more accurate answer!

To find the force necessary to hold the gun in position, we need to consider the recoil force generated by the bullets being fired.

First, we calculate the rate at which bullets are being fired. Given that the machine gun fires 10 bullets per second, the number of bullets fired per second is 10.

Next, we calculate the momentum of each bullet. The momentum (p) of an object can be calculated by multiplying its mass (m) by its velocity (v). In this case, each bullet has a mass of 20 grams (0.02 kg) and a velocity of 1500 m/s. So, the momentum of each bullet (p) is:

p = m * v
= 0.02 kg * 1500 m/s
= 30 kg m/s

Since the rate at which bullets are fired is 10 bullets per second, the total change in momentum per second is:

Δp = 10 * 30 kg m/s
= 300 kg m/s

Now, we use Newton's second law of motion, which states that force (F) is equal to the rate of change of momentum (Δp) per unit time (t):

F = Δp / t

In this case, t is 1 second. So, the force (F) required to hold the gun in position is:

F = Δp / t
= 300 kg m/s / 1 s
= 300 N

Therefore, the force necessary to hold the machine gun in position is 300 Newtons.