i need some help understanding this problem please.

How many moles of O are there in 32.4g N2O5, how many oxygen and nitrogen atoms are there in the 32.4g?

N2 = 28 g/mol

5O =5*16 = 80 g/mol
so N2O5 = 108 g/mol

32.4 g * 1 mol/108 g = .3 moles of N2O5
that is 5*.3 = 1.5 moles of O
1.5 * 6*10^23 = 9*10^23 atoms of O

.6 moles of N
.6*6*10^23 = 3.6*10^23 N atoms

1.5x6.02x10^23=9.03x10^23 (3 sig. figs. as in 32.4) is the correct answer.

1.5 molN2O5

Express your answer using two significant figures.

Oh boy, time to break out the science jokes! Alright, let's tackle this problem.

To find the number of moles of O (oxygen), we need to use the molar mass of N2O5. The molar mass of N2O5 is approximately 108 grams/mol.

So, to find the number of moles of O, we first need to find the mass of O in 32.4g of N2O5. N2O5 has a total of 5 oxygen atoms, and since the molar mass of O is approximately 16 grams/mol, we can calculate:

Mass of O = (Number of O atoms) x (Molar mass of O)
Mass of O = 5 x 16 = 80 grams

Now we can find the number of moles of O by dividing the mass of O by its molar mass:

Number of moles of O = (Mass of O) / (Molar mass of O)
Number of moles of O = 80 / 16 = 5 moles

Now, onto finding the number of oxygen and nitrogen atoms in 32.4g of N2O5. Since one mole of N2O5 contains 5 moles of oxygen atoms and 2 moles of nitrogen atoms, we can use these ratios to find the number of atoms:

Number of O atoms = (Number of moles of O) x (Avogadro's number)
Number of O atoms = 5 x 6.022 x 10^23 (approximately)

Number of N atoms = (Number of moles of N) x (Avogadro's number)
Number of N atoms = 2 x 6.022 x 10^23 (approximately)

And there you have it! Now you should have a better understanding of the problem. I hope that puts a smile on your face!

To solve this problem, we need to use the concept of moles and molar mass. The molar mass is the mass of one mole of a substance and is expressed in grams per mole (g/mol).

First, let's find the molar mass of N2O5.
N2O5 consists of two nitrogen atoms (N) and five oxygen atoms (O). The molar mass of N is 14.01 g/mol, and the molar mass of O is 16.00 g/mol.

So, the molar mass of N2O5 can be calculated as follows:
Molar mass of N2O5 = (2 × molar mass of N) + (5 × molar mass of O)
= (2 × 14.01 g/mol) + (5 × 16.00 g/mol)
= 28.02 g/mol + 80.00 g/mol
= 108.02 g/mol

Now, we can use the molar mass to find the number of moles of N2O5 in 32.4 g.

Number of moles = Mass / Molar mass
= 32.4 g / 108.02 g/mol
= 0.3 mol (rounded to one decimal place)

Now, to find the number of moles of oxygen (O) in 32.4 g of N2O5, we can use the mole ratio.
From the chemical formula N2O5, we know that there are five oxygen atoms in one molecule of N2O5. Therefore, for every one mole of N2O5, there are five moles of O.

Number of moles of O = Number of moles of N2O5 × (moles of O / moles of N2O5)
= 0.3 mol × (5 mol O / 1 mol N2O5)
= 1.5 mol O

Finally, to find the number of oxygen atoms in 32.4 g of N2O5, we multiply the number of moles of O by Avogadro's number.

Number of oxygen atoms = Number of moles of O × Avogadro's number
= 1.5 mol O × (6.022 × 10^23 atoms/mol)
= 9.033 × 10^23 atoms (rounded to three significant figures)

Similarly, we can calculate the number of nitrogen atoms using the mole ratio. From the chemical formula N2O5, we know that there are two nitrogen atoms in one molecule of N2O5. Therefore, for every one mole of N2O5, there are two moles of N.

Number of moles of N = Number of moles of N2O5 × (moles of N / moles of N2O5)
= 0.3 mol × (2 mol N / 1 mol N2O5)
= 0.6 mol N

Number of nitrogen atoms = Number of moles of N × Avogadro's number
= 0.6 mol N × (6.022 × 10^23 atoms/mol)
= 3.613 × 10^23 atoms (rounded to three significant figures)

So, in 32.4 g of N2O5, there are approximately 1.5 moles of O, 9.033 × 10^23 oxygen atoms, and 0.6 moles of N, 3.613 × 10^23 nitrogen atoms.