A hockey player shoots the puck which is initially at rest by applying a force of 72 N through a displacement of 1.6 m. The mass of the puck is 161 grams.

a) Calculate the work done by the player on the puck.

b) Calculate the resulting speed of the puck

Work = gain in kinetic energy = F*d = 72*1.6 Joules

so
(1/2) (.161) v^2 = 72 * 1.6

b) Solve Damon's last equation for v.

To solve this problem, we will make use of the work-energy principle. The work-energy principle states that the work done on an object is equal to the change in its kinetic energy.

a) To calculate the work done by the player on the puck, we need to use the formula:

Work = Force * Displacement * cos(theta)

Where:
- Force is the applied force (in Newtons)
- Displacement is the distance over which the force is applied (in meters)
- theta is the angle between the force and displacement (in this case, since the angle is not given, we assume it to be 0 degrees, so cos(theta) = 1)

Substituting the given values into the formula:

Work = 72 N * 1.6 m * 1

Therefore, the work done by the player on the puck is 115.2 Joules.

b) To calculate the resulting speed of the puck, we can use the work-energy principle again. The work done on an object is equal to its change in kinetic energy. The initial kinetic energy of the puck is zero since it is at rest. Therefore, the work done on the puck is equal to its final kinetic energy:

Work = Change in Kinetic Energy

Change in Kinetic Energy = 1/2 * mass * (final velocity)^2 - 1/2 * mass * (initial velocity)^2

Since the initial velocity is zero, the equation simplifies to:

Work = 1/2 * mass * (final velocity)^2

Substituting the given values:

115.2 J = 1/2 * 0.161 kg * (final velocity)^2

Now we can solve for the final velocity:

final velocity = sqrt(2 * Work / mass)

final velocity = sqrt(2 * 115.2 J / 0.161 kg)

Therefore, the resulting speed of the puck is approximately 15.48 m/s.