Which of these ions have five d electrons in the outermost d subshell?
Mn2+
Fe2+
Re2+
Y2+
Tc2+
Zn2+
Ru2+
ok thanks
So what is the answer
To determine which of these ions have five d electrons in the outermost d subshell, we need to examine the electron configuration of each ion.
The electron configuration of an ion is derived from the neutral atom's electron configuration by adding or removing electrons according to the ion's charge.
Let's examine each ion one by one:
1. Mn2+: The electron configuration of a neutral Mn atom is [Ar] 4s2 3d5. Removing two electrons gives us: [Ar] 4s0 3d5. Thus, Mn2+ has 5 d electrons in the outermost d subshell.
2. Fe2+: The electron configuration of a neutral Fe atom is [Ar] 4s2 3d6. Removing two electrons gives us: [Ar] 4s0 3d6. Thus, Fe2+ has 6 d electrons in the outermost d subshell, not 5.
3. Re2+: The electron configuration of a neutral Re atom is [Xe] 6s2 4f14 5d5. Removing two electrons gives us: [Xe] 6s0 4f14 5d5. Thus, Re2+ has 5 d electrons in the outermost d subshell.
4. Y2+: The electron configuration of a neutral Y atom is [Kr] 5s2 4d1. Removing two electrons gives us: [Kr] 5s0 4d1. Thus, Y2+ has only 1 d electron in the outermost d subshell, not 5.
5. Tc2+: The electron configuration of a neutral Tc atom is [Kr] 5s2 4d5. Removing two electrons gives us: [Kr] 5s0 4d5. Thus, Tc2+ has 5 d electrons in the outermost d subshell.
6. Zn2+: The electron configuration of a neutral Zn atom is [Ar] 3d10 4s2. Removing two electrons gives us: [Ar] 3d10 4s0. Thus, Zn2+ does not have any d electrons in the outermost d subshell.
7. Ru2+: The electron configuration of a neutral Ru atom is [Kr] 5s2 4d7. Removing two electrons gives us: [Kr] 5s0 4d7. Thus, Ru2+ has 7 d electrons in the outermost d subshell, not 5.
Therefore, the ions that have five d electrons in the outermost d subshell are Mn2+, Re2+, and Tc2+.