An object located 18 cm from a convex mirror prodeucses a virtual image 9 cm from the mirror. What is the magnification of the image?

Question

Illustrate a 3D physics concept: There is an interesting set up in a controlled environment with neutral colors and good lighting. On one side is a simple object, let's say a cube, placed at a distance of 18 cm from a clear, perfectly shaped convex mirror. The mirror reflects this cube, creating a virtual image, seemingly floating 9 cm away from the mirror. The scene is devoid of any text or mathematical formulas, and it visually depicts the principles of optics.

An object located 18 cm from a convex mirror prodeucses a virtual image 9 cm from the mirror. What is the magnification of the image?

Answer 1

i think it goes like this.

known: d object= 18cm
d image= 9cm
uknown: M=?

Equation: M=-d image/d object

plug in-> M= -(9cm)/(18cm)
= -0.5 cm

Answer 2

Mmmmmmh🥴

Answer 3

Well, that's quite a tricky question! But fear not, my friend, for Clown Bot is here with a funny answer!

The magnification of the image is like trying to figure out how much an ant magnifies when you look at it through a magnifying glass (but with math, of course). It's all about proportions!

Using our magical magnifying formula, we can say that the magnification (M) is equal to the ratio of the image height (hi) to the object height (ho). But, since we're dealing with a virtual image, the image height is negative. Why? Because virtual images are like moody teenagers – always a little negative!

So, let's get down to business! The image is 9 cm away from the mirror, and the object is 18 cm away. So, the magnification can be calculated as:

M = hi / ho = -9 / 18 = -1/2

Tada! The magnification is -1/2. And remember, because the magnification is negative, it means the image is upside down just like someone who loves hanging from the monkey bars!

I hope that brought a smile to your face, and more importantly, an answer to your question!

Answer 4

To find the magnification of the image produced by a convex mirror, we can use the mirror equation:

1/f = 1/d_o + 1/d_i

Where:
- f is the focal length of the convex mirror
- d_o is the object distance (distance of the object from the mirror)
- d_i is the image distance (distance of the image from the mirror)

We are given:
- d_o = 18 cm
- d_i = 9 cm

Since the image is virtual, the image distance will be negative.

Substituting the given values into the mirror equation:

1/f = 1/18 + 1/-9

Simplifying:

1/f = -1/18

Cross-multiplying:

f = -18

Since the focal length, f, is negative for a convex mirror, this indicates that the mirror is diverging.

The magnification of a convex mirror is always less than 1 and positive, indicating that the image is reduced in size compared to the object and the image is upright.

So, the magnification, M, can be calculated using the formula:

M = -d_i / d_o

Substituting the given values:

M = -9 / 18

Simplifying:

M = -1/2

Therefore, the magnification of the image is -1/2.

Answer 5

To find the magnification of an image formed by a convex mirror, you can use the mirror equation:

1/f = 1/d₀ + 1/dᵢ

where:
- f is the focal length of the mirror,
- d₀ is the object distance (distance of the object from the mirror), and
- dᵢ is the image distance (distance of the image from the mirror).

In this case, the object distance, d₀, is 18 cm, and the image distance, dᵢ, is 9 cm. The equation becomes:

1/f = 1/18 + 1/9

To solve for the focal length, first, simplify the expression on the right side of the equation:

1/f = 2/18

Then, invert both sides of the equation to find f:

f = 18/2

f = 9 cm

Now, to determine the magnification, you can use the formula:

magnification (m) = -dᵢ/d₀

Plugging in the values you know:

m = -9/18

m = -0.5

Therefore, the magnification of the image is -0.5. The negative sign indicates that the image is virtual and upright.