A 1470-kg submarine rises straight up towards the surface. Seawater exerts both an upward buoyant force of 16070 N on the sub, as well as a downward resistive force of 1050 N. What is the submarine's acceleration?
net force= mass*a solve for a.
This is what I tried but it didn't work. Am I doing something wrong?
(16070+1050) = 1470a
= 11.6
Why did you add the forces, they are in opposite direction!
Well I tired the other way and it didn't work either. The answer is 0.418 but I can't figure out how.
net force= bouyant force- weight-resistive force
To find the submarine's acceleration, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.
The net force acting on the submarine is the difference between the upward buoyant force and the downward resistive force. The net force is given by:
Net force = Upward buoyant force - Downward resistive force
Given:
Upward buoyant force = 16070 N
Downward resistive force = 1050 N
Submarine's mass (m) = 1470 kg
Substituting the given values into the equation, we get:
Net force = 16070 N - 1050 N
Net force = 15020 N
Now, we can use Newton's second law to find the acceleration:
Net force = mass × acceleration
15020 N = 1470 kg × acceleration
To find the acceleration, we rearrange the equation:
acceleration = Net force / mass
acceleration = 15020 N / 1470 kg
Using a calculator to perform the division gives us:
acceleration ≈ 10.20 m/s²
Therefore, the submarine's acceleration is approximately 10.20 m/s².