Two thin strings supported a 200g metre ruler 20cm and 30cm from both ends. Calculate the tension in each string.
Since the stick is 100 cm long, one string (with tension T1) is attached 30 cm from the center and the other (T2) is 20 cm away, on the other side of center.
For a balance of the torque about the center, the string closest to center must have 1.5 times as much tension as the other. Total tension for both is
T1 + T2 = M*g = 1.96 N
Since T2 = 1.5*T1 ,
2.5 T1 = 1.96 N
T1 = 0.784 N
T2 = 1.176 N
i dnt know
To calculate the tension in each string, we can use the principle of moments, which states that the sum of the clockwise moments about a point is equal to the sum of the anticlockwise moments about the same point.
Let's consider the point where the two strings support the meter ruler as the pivot. In this case, there are two clockwise moments and one anticlockwise moment.
The clockwise moments are generated by the weight of the meter ruler acting at the center of gravity (which is 10cm from either end) and the tension in each string acting at their respective points of attachment. The anticlockwise moment is generated by the weight of the meter ruler acting at the center of gravity.
We can calculate the tension in each string using the equation:
(Tension in first string * distance from pivot) + (Tension in second string * distance from pivot) = Weight of the meter ruler * distance from pivot
Let's substitute the given values:
(Tension in first string * 20cm) + (Tension in second string * 30cm) = (200g * 10cm)
To simplify the equation, we need to convert grams to kilograms and centimeters to meters:
(Tension in first string * 0.2m) + (Tension in second string * 0.3m) = (0.2kg * 10m)
0.2T + 0.3T = 2
0.5T = 2
T = 2 / 0.5
T = 4
Therefore, the tension in each string is 4 Newtons.