A monkey is sitting on a wood plate attached to a rope whose other end is passed over a tree branch, as shown in the figure. The monkey holds the rope and tries to pull it down. The combined mass of the monkey and the wood plate is 117 kg.
a) What is the minimum force the monkey has to apply to lift off the ground?
b) What applied force is needed to move the monkey with an upward acceleration of 2.71 m/s2?
c) Now assume there is a second monkey standing on the ground and pulling down the rope by himself. What is the minimum force this second monkey has to apply to lift the first monkey on the wood plate off the ground?
d) And what applied force is necessary so that the second monkey on the ground can move the first monkey on the wood plate with an upward acceleration of 2.71 m/s2?
I NEED ONLY ANSWERS OF ESCH QUESTÝONS.. ÝF ANYONE SOLVE THESE PROBLEM. I WÝSH TO SAY LÝKE A) B) C)... THANKS
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a) To find the minimum force the monkey has to apply to lift off the ground, we need to consider the weight of the monkey and the wood plate.
The weight of an object can be calculated using the formula:
Weight = mass x gravity
Since the combined mass of the monkey and the wood plate is given as 117 kg, and the force of gravity is approximately 9.8 m/s^2, we can calculate the weight as:
Weight = 117 kg x 9.8 m/s^2 = 1146.6 N
Therefore, the minimum force the monkey has to apply to lift off the ground is 1146.6 Newtons.
b) To find the applied force needed to move the monkey with an upward acceleration of 2.71 m/s^2, we need to consider the net force acting on the monkey.
Net force = mass x acceleration
In this case, the mass of the monkey is still 117 kg, and the upward acceleration is given as 2.71 m/s^2. Therefore, the applied force can be calculated as:
Applied force = mass x acceleration = 117 kg x 2.71 m/s^2 = 317.07 N
Therefore, the applied force needed to move the monkey with an upward acceleration of 2.71 m/s^2 is 317.07 Newtons.
c) Now, if there is a second monkey standing on the ground and pulling down the rope by himself, we need to consider the forces acting on the system.
Since the first monkey and the wood plate are lifted off the ground, the minimum force the second monkey has to apply is equal to the weight of the first monkey and the wood plate, which is 1146.6 Newtons (calculated in part a).
Therefore, the minimum force the second monkey has to apply to lift the first monkey on the wood plate off the ground is 1146.6 Newtons.
d) To find the applied force necessary for the second monkey on the ground to move the first monkey on the wood plate with an upward acceleration of 2.71 m/s^2, we need to consider the net force acting on the system.
Net force = mass x acceleration
In this case, the mass of the combined system (first monkey and wood plate) is 117 kg, and the desired upward acceleration is 2.71 m/s^2. Therefore, the applied force can be calculated as:
Applied force = mass x acceleration = 117 kg x 2.71 m/s^2 = 317.07 N
Therefore, the applied force necessary for the second monkey on the ground to move the first monkey on the wood plate with an upward acceleration of 2.71 m/s^2 is 317.07 Newtons.
a) To find the minimum force the monkey has to apply to lift off the ground, we need to consider the forces acting on the system. The two main forces we need to consider are the weight of the monkey and the tension in the rope.
The weight of the monkey is given by the formula W = m * g, where m is the mass of the monkey and g is the acceleration due to gravity (approximately 9.8 m/s^2).
In this case, the mass of the monkey is 117 kg, so the weight is 117 kg * 9.8 m/s^2 = 1146.6 N. This is the force pulling the monkey down.
Since the monkey is trying to lift off the ground, the tension in the rope must be equal to or greater than the weight. Therefore, the minimum force the monkey has to apply is 1146.6 N.
b) To find the applied force needed to move the monkey with an upward acceleration of 2.71 m/s^2, we use Newton's second law of motion, which states that force equals mass times acceleration (F = m * a).
In this case, the mass of the monkey is 117 kg and the upward acceleration is 2.71 m/s^2. Therefore, the force needed is 117 kg * 2.71 m/s^2 = 317.07 N.
So, the applied force needed to move the monkey with an upward acceleration of 2.71 m/s^2 is 317.07 N.
c) Now, let's consider the second monkey pulling down the rope by himself. The minimum force this second monkey needs to apply to lift the first monkey on the wood plate off the ground is the same as the tension in the rope.
We already found that the weight of the monkey is 1146.6 N. Therefore, the second monkey needs to apply at least 1146.6 N of force to lift the first monkey on the wood plate off the ground.
d) Finally, let's find the applied force necessary for the second monkey on the ground to move the first monkey on the wood plate with an upward acceleration of 2.71 m/s^2.
To find this force, we need to consider the forces acting on the system again. In this case, the applied force from the second monkey needs to overcome the weight of the first monkey and the wood plate (1146.6 N) and also provide the necessary force for the upward acceleration (317.07 N).
So, the applied force necessary for the second monkey to move the first monkey on the wood plate with an upward acceleration of 2.71 m/s^2 is 1146.6 N + 317.07 N = 1463.67 N.