A solution contains 15 g of CaCl2 in a total volume of 190 mL. Express the concentration in terms of grams/liter, % w/v, molars, and milimolars.
15 g CaCl2/molar mass = mols CaCl2.
mols/L = molarity.
millimolarity is 1000 times that.
% W/V is mass in 100 mL solution.
Oh, concentration! That's a good topic to clown around with! Let's have some fun breaking down the numbers:
To express the concentration in grams/liter, we take the 15 g of CaCl2 and divide it by the volume of the solution in liters. Since we have 190 mL, we need to convert it to liters by dividing by 1000. So, the concentration in grams/liter is 15 g / (190 mL / 1000) L. Ah! Let's do the math... It's approximately 79.0 g/L! Whoop-dee-doo!
Now, for the % w/v, we take the weight of the solute (15 g) and divide it by the volume of the solution (190 mL) times 100. So, it's (15 g / 190 mL) x 100. And that comes out to be approximately 7.9% w/v. Ta-da!
Moving onto molars, we need to calculate the number of moles of CaCl2 present. We divide the weight of CaCl2 (15 g) by its molar mass (40.08 + 2 × 35.45). Then, we divide this by the volume of the solution in liters (190 mL / 1000). And voila! We have the concentration in molars. It's around 0.155 M. Tadaa!
Lastly, let's juggle with milimolars! We need to multiply the concentration in molars (0.155 M) by 1000 to convert it into milimolars. So, it's approximately 155 mM. Hooray!
There you have it, my friend! Concentration expressed in grams/liter, % w/v, molars, and milimolars. Remember, laughter is the best solution!
To express the concentration in terms of grams/liter (g/L), we need to convert the volume from milliliters (mL) to liters (L) and calculate the concentration in grams per liter.
Step 1: Convert volume from mL to L:
190 mL = 190/1000 L = 0.190 L
Step 2: Calculate the concentration in g/L:
Concentration (g/L) = Mass of solute (g) / Volume of solution (L)
Concentration (g/L) = 15 g / 0.190 L = 78.95 g/L
Therefore, the concentration of CaCl2 in terms of grams/liter is 78.95 g/L.
To express the concentration as % w/v (weight/volume), we need to calculate the percentage of the solute weight in the total volume of the solution.
Step 1: Calculate the weight/volume percentage:
% w/v = (Mass of solute (g) / Volume of solution (mL)) x 100
% w/v = (15 g / 190 mL) x 100 = 7.89% w/v
Therefore, the concentration of CaCl2 in terms of % w/v is 7.89% w/v.
To express the concentration in molarity (M), we need to calculate the number of moles of the solute (CaCl2) and divide it by the volume of the solution in liters.
Step 1: Calculate the number of moles of CaCl2:
Moles = Mass of solute (g) / molar mass of CaCl2
Molar mass of CaCl2 = (1 x Atomic mass of calcium) + (2 x Atomic mass of chlorine)
Atomic mass of calcium = 40.08 g/mol
Atomic mass of chlorine = 35.45 g/mol
Molar mass of CaCl2 = (1 x 40.08) + (2 x 35.45) = 111.0 g/mol
Moles = 15 g / 111.0 g/mol = 0.135 moles
Step 2: Convert volume from mL to L:
190 mL = 190/1000 L = 0.190 L
Step 3: Calculate the molarity (M):
Molarity (M) = Moles / Volume (L)
Molarity (M) = 0.135 moles / 0.190 L = 0.711 M
Therefore, the concentration of CaCl2 in terms of molarity is 0.711 M.
To express the concentration in millimolarity (mM), we can convert the molarity to millimoles per liter.
Step 1: Convert molarity to millimolarity:
Millimolarity (mM) = Molarity (M) x 1000
Millimolarity (mM) = 0.711 M x 1000 = 711 mM
Therefore, the concentration of CaCl2 in terms of millimolarity is 711 mM.
To express the concentration in terms of grams/liter, % w/v, molar, and millimolar, we first need to calculate the number of moles of CaCl2 in the solution.
1. Calculate the number of moles of CaCl2:
The molar mass of CaCl2 is 40.08 g/mol (40.08 g/mol for calcium + 2 * 35.45 g/mol for chlorine).
Number of moles = Mass / Molar mass
Number of moles = 15 g / 40.08 g/mol
Number of moles = 0.374 moles
2. Concentration in grams/liter (g/L):
Concentration (g/L) = Mass of solute / Volume of solution
Concentration (g/L) = 15 g / 0.190 L
Concentration (g/L) = 78.95 g/L
3. Concentration in % w/v (weight/volume):
% w/v = (Mass of solute / Volume of solution) * 100
% w/v = (15 g / 0.19 L) * 100
% w/v = 7.89 % w/v
4. Concentration in molar (M):
Molarity = Moles of solute / Volume of solution (in liters)
Molarity = 0.374 mol / 0.19 L
Molarity = 1.968 M
5. Concentration in millimolar (mM):
Millimolarity = Molarity * 1000
Millimolarity = 1.968 M * 1000
Millimolarity = 1968 mM
Therefore, the concentration of CaCl2 in the given solution is:
- 78.95 g/L
- 7.89 % w/v
- 1.968 M (molar)
- 1968 mM (millimolar)