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Write the composite function in the form f(g(x)). [Identify the inner function u=g(x) and the outer function y=f(u).] Then find the derivative dy/dx.

y=√sinx

√ is square root.

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  1. g(x) = sinx
    f(x) = √x

    then f(g(x))
    = f(sinx)
    = √sinx

    if y = fg(x)) = √sinx = (sinx)^(1/2)
    dy/dx = (1/2)(sinx)^(-1/2) (cosx
    = cosx/(2√sinx)

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