If the vertical component of velocity for a projectile is 7.3 meters/second, find its hang time.
A. 1.9 seconds
B. 2.5 seconds
C. 5.6 seconds
D. 6.7 seconds
E. 7.1 seconds
9.8 (gravity) - 7.3 (velocity) = 2.5, B
To find the hang time of a projectile, we can use the equation:
hang time = (2 * vertical component of velocity) / acceleration due to gravity
Given that the vertical component of velocity is 7.3 meters/second, and the acceleration due to gravity is approximately 9.8 meters/second^2, we can substitute these values into the equation:
hang time = (2 * 7.3) / 9.8
hang time ≈ 14.6 / 9.8
hang time ≈ 1.49 seconds
Rounding to one decimal place, the hang time of the projectile is approximately 1.5 seconds.
None of the options given (A, B, C, D, E) match the calculated hang time.
To find the hang time of a projectile, we can use the formula:
hang time = (2 * vertical component of velocity) / acceleration due to gravity
In this case, the vertical component of velocity is given as 7.3 meters/second. The acceleration due to gravity is approximately 9.8 meters/second^2.
Plugging in the values into the formula, we get:
hang time = (2 * 7.3) / 9.8
= 14.6 / 9.8
= 1.49 seconds (rounded to two decimal places)
Therefore, the hang time of the projectile is approximately 1.49 seconds.
Since none of the answer choices match exactly, we need to round our answer. Looking at the options, the closest answer is 1.9 seconds (option A).
So the correct answer is A. 1.9 seconds.
v = vi - g t
at top v = 0
0 = 7.3 - 9.8 t
t = .745 s to top
same amount falling back so
2 * t = 1.49 seconds in the air
Now that is quite enough. You try some.