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At some other temperature, a solid sample of Ca(OH)2 is shaken with 0.0100 M CaCl2.

Once equilibrated, some solid Ca(OH)2 remains undissolved.
The solution is filtered and a 20.00 mL sample requires 38.80 mL of 0.0100 M HCl to neutralize it.
Calculate the value for Ksp of Ca(OH)2 from this data

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  1. Ca(OH)2 ==> Ca^2+ + 2OH^-

    Ksp = (Ca^2+)(OH^-)^2
    (Ca^2+) = 0.01M from the CaCl2.
    (OH^-) = from the HCl data.
    mols HCl = M x L = 0.01M x 0.03880L = ?
    (OH^-) = 1/2 x that since there are two H^+ required for the Ca(OH)2

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