Ba(OH)2(aq)+2CH3COOH(aq)=Ba(CH3COO)2(aq)+2(l)H2O what is the net ionic equation with phases?

2CH3COOH(aq)+Ba(OH)2(aq)→Ba(CH3COO)2(aq)+2H2O(l)

I need the balanced net ionic equation.

To determine the net ionic equation with phases for the given reaction:

Ba(OH)2(aq) + 2CH3COOH(aq) = Ba(CH3COO)2(aq) + 2H2O(l)

We first need to write the balanced chemical equation.

1. Write the balanced equation:
Ba(OH)2(aq) + 2CH3COOH(aq) = Ba(CH3COO)2(aq) + 2H2O(l)

2. Split the reactants and products into their respective ions:
Ba^2+(aq) + 2OH^-(aq) + 2CH3COO^-(aq) = Ba^2+(aq) + 2CH3COO^-(aq) + 2H2O(l)

3. Eliminate the spectator ions (ions that appear on both sides of the equation and do not participate in the reaction). In this case, the spectator ions are Ba^2+ and CH3COO^-.

4. Write the net ionic equation by excluding the spectator ions:
2OH^-(aq) + 2H^+(aq) = 2H2O(l)

So, the net ionic equation with phases for the given reaction is:
2OH^-(aq) + 2H^+(aq) = 2H2O(l)

To find the net ionic equation, we need to first write out the balanced molecular equation. Then, we'll break down the soluble ionic compounds into their respective ions. Finally, we'll cancel out any spectator ions to obtain the net ionic equation.

The given balanced molecular equation is:
Ba(OH)2(aq) + 2CH3COOH(aq) → Ba(CH3COO)2(aq) + 2H2O(l)

To write the equation using ions, we'll first dissociate the soluble compounds into their individual ions:

Ba(OH)2(aq): Ba2+(aq) + 2OH-(aq)
CH3COOH(aq): CH3COO-(aq) + H+(aq)

The final balanced ionic equation is:
Ba2+(aq) + 2OH-(aq) + 2CH3COO-(aq) + 2H+(aq) → Ba(CH3COO)2(aq) + 2H2O(l)

Now, let's determine the spectator ions, which are ions that appear on both sides of the equation and do not undergo any change during the reaction. In this case, the spectator ions are Ba2+(aq) and 2CH3COO-(aq).

Removing the spectator ions, we get the net ionic equation:
2OH-(aq) + 2H+(aq) → 2H2O(l)

Therefore, the net ionic equation with phases is:
2OH-(aq) + 2H+(aq) → 2H2O(l)

2(OH^-)(aq) + 2H^+(aq) ==> 2H2O(l)

Do you know how to do these?