determine the specific heat of a 150.0 gram object that requires 62.0 cal of energy to raise its temperature 12.0 C.
q = 62 = mass x specific heat x 12
Substitute and solve for sp. h.
Determine the specific heat of a 150.0 gram object that requires 786J of energy to raise its temperature 12.0 °C. c=Q/mΔ?
Step 1: Recall the formula for specific heat:
Q = mcΔT
where Q is the amount of heat energy transferred, m is the mass of the object, c is the specific heat, and ΔT is the change in temperature.
Step 2: Identify the known values from the given information:
- Mass (m) of the object = 150.0 grams
- Heat energy (Q) required = 62.0 cal
- Change in temperature (ΔT) = 12.0°C
Step 3: Substitute the known values into the formula:
62.0 cal = (150.0 g) * c * 12.0°C
Step 4: Solve for the specific heat (c):
c = 62.0 cal / (150.0 g * 12.0°C)
Step 5: Calculate the specific heat:
c ≈ 0.0347 cal/(g°C)
Therefore, the specific heat of the object is approximately 0.0347 cal/(g°C).
To determine the specific heat of an object, we'll use the formula:
q = mcΔT
Where:
q = amount of energy transferred (in calories)
m = mass of the object (in grams)
c = specific heat of the object (in calories/gram degree Celsius)
ΔT = change in temperature (in degree Celsius)
Given:
m = 150.0 grams
q = 62.0 cal
ΔT = 12.0 °C
Now, rearranging the formula to solve for c:
c = q / (m * ΔT)
Substituting the given values into the formula:
c = 62.0 cal / (150.0 g * 12.0 °C)
To get the answer, perform the calculations:
c = 0.0344 cal/g °C
Therefore, the specific heat of the 150.0 gram object is approximately 0.0344 cal/g °C.