Two point charges, Q1 = 6.7 µC and Q2 = 1.2 µC are located between two oppositely charged parallel plates. The two charges are separated by a distance of x = 0.32 m. Assume that the electric field produced by the charged plates is uniform and equal to E = 75000 N/C. Calculate the net electrostatic force on Q1 and give its direction.
My solution:
ForceQ1 = Force P + Force Q2
Fp = EQ1
FQ2 =kQ1Q2/ x^2
= (75000 x 6.7 x 10^6) + [9x10^9 x 6.7 µC x 1.2 µC]/ 0.32^2
FQ1 = 0.20N
but webassign says i'm wrong. Can someone help?
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2 answers

I do not see the geometry diagram. Are you sure you have the signs correct? Try subtracting instead of adding. That seems the most likely error. Your general idea is fine.
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answered by Damon 
(75000*6.7*10^6)(9*10^9*6.7*10^6*1.2*10^6)/0.32^2
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answered by Anonymous
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