The sum of the digits of a two-digit number is 12, and the units digit is twice the tens digit. Find the number.
let the tens digit be a
then the unit digit is 2a
it says ... a + 2a = 12
mmmhh?
Can you finish it?
To find the two-digit number, we need to find the tens digit and the units digit.
Let's represent the tens digit as 'T' and the units digit as 'U'.
From the given information:
1. The sum of the digits is 12, so we have the equation: T + U = 12.
2. The units digit is twice the tens digit, so we have the equation: U = 2T.
We can solve these two equations simultaneously to find the values of T and U.
Substituting the value of U from the second equation into the first equation, we get:
T + 2T = 12
3T = 12
T = 4
Now, substitute the value of T into the second equation to find U:
U = 2T = 2 * 4 = 8
Therefore, the tens digit is 4 and the units digit is 8. Thus, the two-digit number is 48.