What is the formula weight of Li2CO3?
73.891 amu
b. What is the mass of 1.30 x 10-4 mol of Li2CO3?
9.61E-3
c. How many moles of CO32- ions are present in 102 g of Li2CO3?
Dont get how to compute
102g Li2CO3 x (1 mol Li2CO3/73.891g Li2CO3) x (1 mol CO3^2-/1 mol Li2CO3) = ?
The first term (102 x 1/73.891 converts 102 g Li2CO3 to moles Li2CO3. The second term tells you that there is 1 mol CO3^2- ions in 1 mol Li2CO3, another way of saying that since there is 1 mole CO3/mol Li2CO3 then moles Li2CO3 = mol CO3^2-
so the answer would be 1.38 moles
yes
To compute the number of moles of CO32- ions present in 102 g of Li2CO3, you can follow these steps:
1. Determine the molar mass of Li2CO3:
- The molar mass of Li is approximately 6.94 g/mol.
- The molar mass of C is approximately 12.01 g/mol.
- The molar mass of O is approximately 16.00 g/mol.
- Multiply the molar mass of each element by the corresponding subscript and sum them up to get the molar mass of Li2CO3.
- Molar mass of Li2CO3 = (2 * molar mass of Li) + molar mass of C + (3 * molar mass of O)
2. Calculate the number of moles of Li2CO3:
- Divide the given mass of Li2CO3 (102 g) by its molar mass.
- Moles of Li2CO3 = Mass of Li2CO3 / Molar mass of Li2CO3
3. Determine the moles of CO32- ions:
- Notice in the formula Li2CO3, there is only one CO32- ion.
- The number of moles of CO32- ions in Li2CO3 is equal to the number of moles of Li2CO3 (from step 2) since there is a 1:1 ratio.
By following these steps, you can compute the number of moles of CO32- ions in the given mass of Li2CO3.