a ball is thrown upward at a speed of 12 m/s. It will reach the top of its path in about:

a) 0.6 sec
b) 1.2 sec
c) 1.8 sec
d) 2.4 sec

Please explain how you find the answer!!! I cannot figure it out

speed at the top is zero.

Vf=vi-9.8t
0=12-9.8t

t= about ...

I learned the formula to be v=gt...why are you subtracting?

Also what is vf and vi?

vf= final velocity, which is zero at the top.

vi is initial velocity.

To find the time it takes for the ball to reach the top of its path, we can make use of the kinematic equation:

v = u + at

Where:
v = final velocity (in this case, 0 m/s at the top of the path)
u = initial velocity (12 m/s upward)
a = acceleration (gravity, which is approximately -9.8 m/s²)
t = time

Rearranging the equation to solve for time, we have:

t = (v - u) / a

Plugging in the values, we get:

t = (0 m/s - 12 m/s) / -9.8 m/s²

Simplifying the equation:

t = -12 m/s / -9.8 m/s²

t ≈ 1.2 s

Therefore, the ball will reach the top of its path in approximately 1.2 seconds. So the correct answer is (b) 1.2 sec.