Write an equation of the line containing the given point and parallel to the given line. (6,-7):9x-8y=3 The equation of the line is y=
Solve for the slope of the 9x-8y=3. You get y= 9/8x - 3/8. So your slope is 9/8. Because the line is parallel. You then use point slope formula to get equation of line in y=mx+b form.(slope form).
So y-y1=m(x-x1)
y-(-7)=9/8(x-6)
y+7=9/8(x-6)
So y=9/8x -55/4
I did the math in my head so double check the arithmetic.
Wow, I must say, equations are like riddles to me. But fear not, for I am the Clown Bot here to solve your equation puzzles with a splash of humor!
To find a line parallel to the given line, we need to make sure it has the same slope. So let's start by finding the slope of the given line:
9x - 8y = 3
First, let's rearrange the equation to get it in the "y = mx + b" form, where "m" represents the slope:
-8y = -9x + 3
Dividing both sides by -8, we get:
y = (9/8)x - 3/8
So the slope of the given line is 9/8.
Now, we can use the point-slope formula to find the equation of the line:
y - y1 = m(x - x1)
Plug in the values of the point (6, -7) and the slope (9/8):
y - (-7) = (9/8)(x - 6)
Simplify:
y + 7 = (9/8)x - (54/8)
Combine like terms:
y = (9/8)x - (54/8) - (56/8)
Yikes, I got tangled in all those fractions! Let me simplify that for you:
y = (9/8)x - (110/8)
So the equation of the line parallel to the given line and passing through the point (6, -7) is:
y = (9/8)x - (110/8)
Remember, if math ever gets too serious, just add a little clownish humor to it!
To find the equation of a line parallel to a given line, we need to use the same slope as the given line.
First, let's rearrange the equation of the given line in slope-intercept form y = mx + b, where m is the slope and b is the y-intercept.
9x - 8y = 3
-8y = -9x + 3
Divide both sides by -8:
y = (9/8)x - 3/8
Now, we know that the slope of the given line is 9/8. Since we want to find a line parallel to this given line, the slope of the parallel line will also be 9/8.
Next, we have the point (6,-7) that the line passes through. We can use the point-slope form of a linear equation to find the equation of the parallel line.
The point-slope form of a linear equation is:
y - y1 = m(x - x1)
Where m is the slope, and (x1, y1) is a point on the line.
Plugging in the values, we have:
y - (-7) = (9/8)(x - 6)
Simplifying:
y + 7 = (9/8)x - 54/8
Combining like terms:
y = (9/8)x - 61/8
So, the equation of the line containing the point (6,-7) and parallel to the line 9x - 8y = 3 is:
y = (9/8)x - 61/8
sorry i got a wrong slope... this is the correct answer...
9x-8y=3
(-8y=-9x+3)/-8
y=9/8x - 3/8
m=9/8
given: m= 9/8 and (6,-7)
y-(-7)=9/8(x-6)
y+7=9/8x-27/4
y=9/8x-27/4-7
y=9/8x-55/4 final answer...
9x-8y=-2
First, get the slope of the equation by writing it in the form y=mx+b.
given: 9x-8y=3
(-8y=-9x+3)/-8
y=8/9x-3/8
slope=8/9
use point-slope form
m=8/9 and (6,-7)
y-(-7)=8/9(x-6)
y+7=8/9x-48/9
y=8/9x-48/9-7
Final answer: y=8/9x - 37/3