the ratio of the mass of flour in packet A to the mass of of flour in packer B is 1:2.Mrs Anand uses 1/3 of the flour in packet A.What is the new ratio of the mass of folur in packet A to the mass of flour in packet B? pls give ur answer clearly
a/b = 1/2
(2/3 a)/b = 2/3 * a/b = 2/3 * 1/2 = 1/3
the ratio of the mass of flour in packet A to the mass of flour packet B is 1 : 2. Mrs Anand uses 1/3 of the flour in packet A what is the new ratio of the mass of flour in packet A to the mass of flour in packet B
To determine the new ratio of the mass of flour in packet A to the mass of flour in packet B, we need to calculate the remaining amounts of flour in each packet after Mrs Anand uses 1/3 of the flour in packet A.
Let's start by assigning variables to the masses of flour in each packet. Let "x" represent the mass of flour in packet A, and "y" represent the mass of flour in packet B.
Given that the ratio of the mass of flour in packet A to packet B is 1:2, we can write the equation:
x/y = 1/2
Next, we need to determine the remaining amount of flour in packet A after Mrs Anand uses 1/3 of it. Since she uses 1/3 of packet A's flour, the remaining amount will be 2/3 of the original mass:
Remaining flour in packet A = 2/3 * x
Now, we can substitute this value into the equation:
(2/3 * x) / y = 1/2
To simplify the equation, we can multiply both sides by 2 to remove the fraction:
2 * (2/3 * x) / y = 2 * (1/2)
4/3 * x / y = 1
Finally, we can cross-multiply to solve for the remaining ratio:
4x = 3y
Therefore, the new ratio of the mass of flour in packet A to the mass of flour in packet B is 4:3.
In summary, the new ratio is 4:3, which means the mass of flour in packet A is 4 units compared to the mass of flour in packet B, which is 3 units.