Ok so i looked at it and tried to figure out the conj. base and acid. Are these right?

1) S2-(aq) + HCl(aq) <=>Cl1-(aq) + HS1-(aq)
This is what I think it is:
Acid = HCl
Base = S^2-
Conjugate acid =HS^1-
Conjugate base = Cl^1-

2) H2O2(aq) + PO43-(aq) <=>HPO42-(aq) + HO21-(aq)
This is what I think it is:
Acid = H2O2
Base = PO4^3-
Conjugate acid =HPO4^2-
Conjugate base = HO2^1-

3) IO31-(aq) + HI(aq)<=> I1-(aq) + HIO3(aq)
This is what I think it is:
Acid = HI
Base = IO3
Conjugate acid =HIO3
Conjugate base = I^1-

Those look ok to me.

Let's go through each reaction and determine the correct identification of acids, bases, conjugate acids, and conjugate bases:

1) S2-(aq) + HCl(aq) <=> Cl1-(aq) + HS1-(aq)
In this reaction, HCl donates a proton (H+) to S2-, which makes it an acid. S2- accepts the proton, making it a base. The products of the reaction, Cl1- and HS1-, can be considered as the conjugate base and conjugate acid, respectively.

Correct identification:
Acid: HCl
Base: S2-
Conjugate acid: HS1-
Conjugate base: Cl1-

2) H2O2(aq) + PO43-(aq) <=> HPO42-(aq) + HO21-(aq)
H2O2 loses a proton (H+), so it acts as an acid. PO43- accepts the proton, so it acts as a base. The resulting species after the reaction, HPO42- and HO21-, can be considered as the conjugate acid and conjugate base, respectively.

Correct identification:
Acid: H2O2
Base: PO43-
Conjugate acid: HPO42-
Conjugate base: HO21-

3) IO31-(aq) + HI(aq) <=> I1-(aq) + HIO3(aq)
In this reaction, HI donates a proton (H+) to IO31-, making it an acid. IO31- accepts the proton, making it a base. The products of the reaction, I1- and HIO3, can be considered as the conjugate base and conjugate acid, respectively.

Correct identification:
Acid: HI
Base: IO31-
Conjugate acid: HIO3
Conjugate base: I1-

Overall, your identifications are correct for all three reactions. Remember that acids donate protons (H+), bases accept protons, conjugate acids are formed when a base accepts a proton, and conjugate bases are formed when an acid donates a proton.