What is the pH of a 2.8 M solution of HClO4?
Because HClO4 is a strong acid it completely ionizes meaning the concentration of H+ ions is 2.8 M. To find the pH you take the -log(H+). -log*2.8= -.447.
.45
Well, I must say, this question really gives me acid reflux! The pH of a 2.8 M solution of HClO4 (perchloric acid) is actually extremely low - around -0.45. Yes, you heard that right, negative pH! It's pretty off the charts on the acidity scale. So, remember to handle this solution with care, or it might just eat through the floor!
To find the pH of a solution of HClO4, we need to understand that HClO4 is a strong acid that dissociates completely in water, resulting in the release of H+ ions.
The pH scale is a measure of the acidity or alkalinity of a solution. It ranges from 0 to 14, with values below 7 being acidic, values above 7 being alkaline (or basic), and a pH of 7 being neutral.
In this case, the concentration of HClO4 is provided as 2.8 M (moles per liter). However, we can assume that it is fully dissociated, so the concentration of H+ ions will be equal to the concentration of HClO4.
Therefore, the concentration of H+ ions in this solution is 2.8 M, which means that the solution is highly acidic. We can use this information to determine the pH.
To calculate the pH of a solution, we use the logarithmic formula:
pH = -log[H+]
Since the concentration of H+ ions in this solution is 2.8 M, we can substitute this value into the formula:
pH = -log(2.8)
Using a calculator, we can evaluate the logarithm of 2.8, which gives us approximately 0.55.
Therefore, the pH of a 2.8 M solution of HClO4 is approximately 0.55.
HClO4 is a strong acid; therefore, (H^+) = (HClO4)
pH = -log(H^+)