Please help me solve !!!

Water flows into a swimming pool at the rate
of 9.83 gal/min.
If the pool dimensions are 33.4 ft wide,
44.9 ft long and 19.9 ft deep, how long does
it take to fill the pool? (1 gallon = 231 cubic
inches)
Answer in units of min

1 gallon = 231/1728 = 0.13368 ft^3

Pool volume = 33.4x44.9x19.9
= 29,843 ft^3
= 223,243 gallons

Divide that by the fill rate for the time required.

I have never heard of a swimming pool that deep

To find out how long it takes to fill the pool, we need to calculate the volume of the pool and then divide it by the rate at which water flows into the pool.

Step 1: Convert the dimensions of the pool from feet to inches, as we are given the conversion factor that 1 gallon is equal to 231 cubic inches.
- Width: 33.4 ft = 33.4 ft * 12 in/ft = 400.8 inches
- Length: 44.9 ft = 44.9 ft * 12 in/ft = 538.8 inches
- Depth: 19.9 ft = 19.9 ft * 12 in/ft = 238.8 inches

Step 2: Calculate the volume of the pool in cubic inches.
- Volume = Width * Length * Depth
- Volume = 400.8 inches * 538.8 inches * 238.8 inches = 51,953,700.48 cubic inches

Step 3: Convert the volume of the pool from cubic inches to gallons.
- Volume (gallons) = Volume (cubic inches) / 231
- Volume (gallons) = 51,953,700.48 cubic inches / 231 = 224,867.60 gallons

Step 4: Determine the time required to fill the pool.
- Time (min) = Volume (gallons) / Flow rate (gal/min)
- Time (min) = 224,867.60 gallons / 9.83 gal/min = 22,900.55 min

Final Answer: It will take approximately 22,900.55 minutes to fill the pool.