Equal groups riddle.
I am a number between 20 and 30. When you put me into 6 equal groups, there is an even number in each group and 1 is left over.
its 25 because if you subtract 1 from 25, it is 24 and then you can divide 24 into 6 groups with 1 left over
$2.72 divided by 4
21-5=66
The answer is 25 because you can times 6 by 4 to get 24 and then add one for the one left over
To find the number that satisfies the given conditions, we can start by narrowing down the range from 20 to 30. One approach is to check if each number in this range, when divided into six equal groups, leaves one number as a remainder.
Let's go through each number in the given range and test this condition:
For 20, dividing it into six equal groups results in 20/6 = 3 remainder 2. Since the remainder is not 1, we can eliminate 20 as the answer.
For 21, 21/6 = 3 remainder 3. Again, the remainder is not 1, so we can eliminate 21 as the answer.
For 22, 22/6 = 3 remainder 4. The remainder is still not 1, so we can eliminate 22.
For 23, 23/6 = 3 remainder 5. The remainder continues to not be 1, so we can eliminate 23.
For 24, 24/6 = 4 remainder 0. Finally, we have found a number that satisfies the condition for being evenly divisible into six equal groups. However, since the remainder is 0 and not 1, we can eliminate 24 as well.
For 25, 25/6 = 4 remainder 1. Bingo! We have found a number that fits the criteria. When you put 25 into 6 equal groups, there will be an even number in each group, and 1 will be left over.
Therefore, the answer to the riddle is 25.