Please explain how to solve:

Reid and Maria both play soccer. This season, Reid scored 4 less than twice the number of goals that Maria scored. The difference in the number of goals they scored was 6. How many goals did each of them score?

You have to learn to "translate" the English into Math

In this case there are two unknowns, the number of goals scored by Maria and the number of goals scored by Reid.
You are told a relationship between them
I usually define the smaller quantity, in this case the number of goals scored by Maria
Let the number of goals scored by Maria be x
We are told: "Reid scored 4 less than twice the number of goals that Maria scored"

".. twice the number of goals that Maria scored" --- > 2x
" 4 less than ...." --->2x - 4

So now we have Maria scoring x goals and
Reid scoring 2x-4 goals

"The difference in the number of goals they scored was 6" translated ...
(2x-4) - (x) = 6
2x-4-x = 6
x = 10

so Maria scored 10
Reid scored 2(10)-4 or 16

See how easy it is?

Well, it sounds like Reid and Maria were quite the soccer stars! Let's figure out their goal-scoring shenanigans.

Let's assume that Maria scored "x" goals. According to the problem, Reid scored 4 less than twice the number of goals Maria scored. That means Reid scored (2x - 4) goals.

Now, the problem tells us that the difference in the number of goals they scored was 6. So we can set up an equation: (2x - 4) - x = 6.

Let's do some math magic! Simplifying the equation gives us:
2x - 4 - x = 6
x - 4 = 6
x = 10

So we found out that Maria scored 10 goals. Now, let's substitute that value back into the equation for Reid's goals:
2(10) - 4 = 16

Voila! Reid scored 16 goals. So, to sum it up:
Maria scored 10 goals and Reid scored 16 goals.

And now they can celebrate their fantastic soccer skills with a victory dance!

To solve this problem, let's assign variables to represent the number of goals Reid and Maria scored.

Let's say:
Let R = the number of goals Reid scored
Let M = the number of goals Maria scored

According to the problem, Reid scored 4 less than twice the number of goals Maria scored:
R = 2M - 4 ---(Equation 1)

It is also given that the difference in the number of goals they scored was 6:
R - M = 6 ---(Equation 2)

Now we have a system of two equations with two unknowns:

Equation 1: R = 2M - 4
Equation 2: R - M = 6

We can solve this system using the substitution or elimination method.

Let's use substitution method to solve this system:

1. Substitute the value of R from Equation 1 into Equation 2:
(2M - 4) - M = 6

2. Simplify the equation:
2M - 4 - M = 6
M - 4 = 6

3. Add 4 to both sides of the equation:
M - 4 + 4 = 6 + 4
M = 10

So, Maria scored 10 goals.

4. Now, substitute the value of M into Equation 1 to find the value of R:
R = 2M - 4
R = 2(10) - 4
R = 20 - 4
R = 16

Therefore, Reid scored 16 goals.

In conclusion, Reid scored 16 goals, and Maria scored 10 goals.

To solve this problem, we can use algebra. Let's assign variables to represent the number of goals Reid and Maria scored.

Let's say R represents the number of goals Reid scored, and M represents the number of goals Maria scored.

From the problem, we know that Reid scored 4 less than twice the number of goals that Maria scored. This can be written as the equation:

R = 2M - 4

We also know that the difference in the number of goals they scored was 6, which means Reid's goals minus Maria's goals equals 6. This can be written as the equation:

R - M = 6

Now we have a system of two equations:

R = 2M - 4
R - M = 6

We can solve this system of equations to find the values of R and M.

First, we can substitute the value of R from the first equation into the second equation:

(2M - 4) - M = 6

Simplifying this equation, we get:

2M - M - 4 = 6
M - 4 = 6

Adding 4 to both sides of the equation, we get:

M = 10

Now that we know the value of M, we can substitute it back into the first equation to find the value of R:

R = 2(10) - 4
R = 20 - 4
R = 16

So Reid scored 16 goals and Maria scored 10 goals.