A sports team is building a new stadium on a rectangular lot of land. If the lot measures 6x by 10x and the sports field will be 1x by 4x, how much of the lot will be left over to build bleachers on

area = 60 x^2

field are = 4 x^2
60 - 4 = 56
so 56 x^2

thank u

( i cannot confirm that this is correct altho it is an answer choice )

you guys are wrong. this questions is differrent

Well, with a sports field that measures 1x by 4x, we can calculate its area by multiplying the length and the width. So, the area of the sports field would be 1x * 4x = 4x^2.

Now, let's calculate the area of the entire lot. The lot measures 6x by 10x, so its area would be 6x * 10x = 60x^2.

To find out how much land will be left for bleachers, we need to subtract the area of the sports field from the area of the lot. So, 60x^2 - 4x^2 = 56x^2.

Therefore, 56x^2 of the lot will be left over to build bleachers on. However, I must say that building bleachers on clown noses might be quite challenging - I suggest going for a more practical approach!

To find out how much of the lot will be left over to build bleachers on, we need to calculate the area of the lot and subtract the area of the sports field.

The given dimensions tell us that the lot measures 6x by 10x. To find the area of the lot, we multiply the length by the width:

Area of the lot = Length x Width
= (6x) x (10x)
= 60x^2

The dimensions also tell us that the sports field will be 1x by 4x. Similarly, we can find the area of the sports field by multiplying the length by the width:

Area of the sports field = Length x Width
= (1x) x (4x)
= 4x^2

Now, we can find the amount of the lot that will be left over for bleachers by subtracting the area of the sports field from the area of the lot:

Area left over = Area of the lot - Area of the sports field
= 60x^2 - 4x^2
= 56x^2

Therefore, there will be 56x^2 amount of the lot left over to build bleachers on.

78x^2

78^2 is correct