Segment DF bisects angle EDG. Find FG.
segment EF is n+9
segment FG is 4n-6
Please Help me on this one question! I'd really appreciate it!
Thank You :)!
aye steve man its been almost a decade. Crazy stuff dude.
There's more info needed here.
Unless you know the distances DE and DG there's no way to be sure about EF and FG.
DF could be a very long line, DE could be short, and DG could be medium-length.
However, making the assumption that DE = EG, then we can make some headway.
In that case, EF = FG and so
n+9 = 4n-6
3n = 15
n=5
so EF = FG = 14