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Factor completely or state that this is prime (cannot be factored)

2y^4 + 28y^3 + 98y^2

Note: x^2 is x-squared (that is, x with the superscript 2), etc.

2y^4 + 28y^3 + 98y^2 = 2 y^2 (y^2 + 14 y + 49)

The last expression (in parentheses) is a perfect square, and can be factored again. See if you can finish it.

2y^2[(y = 7)]^2
Is that right?

If you change the = sign to a + sign (an obvious typo), yes, that is right.

Thank you

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Bekki

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