The coordinates of the vertices of CDE are C(1, 4), D(3, 6), and E(7, 4). If the triangle is reflected over the line y = 3, what are the coordinates of the image of D?
It is not 3,-6 it is actually 3,0
the answers are as follows
1 -3,-1
2 3,0
3. the image and the preimage have different orientations
4. x=2
5. -5,7
hope this helps anyone :)
This one is fairly easy. The x-coordinates do not change, since we are rotating around a horizontal axis.
For the y-coordinates, just figure the distance above or below y=3, and change them to the same distance below or above.
(1,4) is 1 unit above y=3. Make it one unit below: (1,2)
similarly,
(3,6) -> (3,3-(6-3)) = (3,0)
(7,4) -> (7,3-(4-3)) = (7,2)
UNIT 5 Transformations LESSON 2 Reflections (October 2022)
(Q1) in the graph below, point D is reflected across the y-axis. what are the coordinates of this image?
(Answer) (-3,-1)
(Q2)the coordinates of the vertices of △CDE are C(1,4), D(3,6), and E(7,4). if the triangle is reflected over the line y=3, what are the coordinates of the image of D?
(Answer) (3,0)
(Q3)what is true for an image and a preimage in a reflection?
(Answer) The image and the preimage have different orientation.
(Q4) In the graph below, what is the line of reflection for △XYZ and △X'Y'Z'?
(Answer) x=2
(Q5) what is the image of A(3,-1) after a reflection, first across the line y=3, and the across the line x=-1?
(Answer) (-5,7)
Mathematician is right!!
Hu
aye shout out shadow mountain high
Rodney Copperbottom is correct
Can confirm! Rodney's right.
To find the coordinates of the image of D after reflecting the triangle over the line y = 3, we need to apply the reflection transformation.
The reflection of a point over a line y = a can be found by subtracting the y-coordinate of the point from twice the line's y-coordinate and keeping the x-coordinate unchanged.
In this case, the line of reflection is y = 3, so we need to subtract the y-coordinate of D (6) from twice the line's y-coordinate (2 * 3 = 6) and keep the x-coordinate of D (3) unchanged.
So the y-coordinate of the image of D will be:
y = 2 * 3 - 6 = 0
Thus, the coordinates of the image of D will be (3, 0).