a gazelle was running at 14m/s does not see the high cliff aheadthe next day buzzards are seen circlinga spot 33 meters from the base of the cliff how high was this cliff?

To find the height of the cliff, we can use the equation of motion. We know that the horizontal distance covered by the gazelle before falling off the cliff is 33 meters. Additionally, we are given the initial velocity (14 m/s) in the horizontal direction.

First, let's calculate the time it took for the gazelle to reach the cliff using the horizontal distance and the initial velocity:

Distance = Velocity × Time
33 meters = 14 m/s × Time

Rearranging the equation, we can solve for time:

Time = Distance / Velocity
Time = 33 meters / 14 m/s
Time ≈ 2.357 seconds

Now, we need to find the vertical distance (height) fallen by the gazelle during this time. We can use the equation of motion for vertical motion:

Height = (1/2) × acceleration × time²

Since the gazelle is falling vertically, we can assume an acceleration due to gravity of approximately 9.8 m/s² (on Earth):

Height = (1/2) × 9.8 m/s² × (2.357 seconds)²
Height ≈ 54.02 meters

Therefore, the height of the cliff is approximately 54.02 meters.

so similar to the last question that you should be able to do it.