A hockey player strikes a puck that is initially at rest. The force exerted by the stick on the puck is 950 N, and the stick is in contact with the puck for 4.4 ms (0.0044 s).

(a) Find the impulse imparted by the stick to the puck.

(b) What is the speed of the puck (m = 1.70 kg) just after it leaves the hockey stick?

a) impulse = Force * time of interaction

i = 950N *.0044s = 4.18N-s
don't know how to do B

b) Just use the momentum equation P= mv and rearrange to use the momentum from a) and the mass they give.

P=mv
V= P/m
V= 4.18N•s/1.70kg
V= 2.6m/s

To find the impulse imparted by the stick to the puck, we can use the formula:

Impulse = Force × Time

Given:
Force exerted by the stick on the puck (F) = 950 N
Time the stick is in contact with the puck (Δt) = 0.0044 s

(a) Impulse = Force × Time
Impulse = 950 N × 0.0044 s
Impulse ≈ 4.18 N.s

Therefore, the impulse imparted by the stick to the puck is approximately 4.18 N.s.

To find the speed of the puck just after it leaves the hockey stick, we can use the formula for impulse:

Impulse = Change in momentum

Given:
Impulse (J) = 4.18 N.s
Mass of the puck (m) = 1.70 kg

(b) Impulse = Change in momentum
J = mv - mu

Initial velocity of the puck (u) is zero (since the puck is initially at rest).
Final velocity of the puck (v) = ?

J = mv - mu
4.18 N.s = (1.70 kg) × (v - 0)

4.18 N.s = 1.70 kg × v

v = 4.18 N.s / 1.70 kg

Therefore, the speed of the puck just after it leaves the hockey stick is approximately 2.46 m/s.

To find the impulse imparted by the stick to the puck, you can use the formula:

Impulse = Force x Time

In this case, the force exerted by the stick on the puck is 950 N, and the contact time is 0.0044 s.

(a) Impulse = 950 N x 0.0044 s = 4.18 Ns

So, the impulse imparted by the stick to the puck is 4.18 Ns.

To find the speed of the puck just after it leaves the hockey stick, you can use the principle of conservation of momentum.

The momentum of an object is given by the formula:

Momentum = Mass x Velocity

We know that the mass of the puck is 1.70 kg.

(b) Before the puck was struck, it was at rest, so its initial momentum was zero.

Since momentum is conserved, the final momentum of the puck just after it leaves the hockey stick is also zero (assuming no external forces act on the puck).

So, we can set up an equation using the principle of conservation of momentum:

Initial momentum + Impulse = Final momentum

Since the initial momentum is zero and the impulse is 4.18 Ns, we have:

0 + 4.18 Ns = 1.70 kg x Velocity

Simplifying the equation:

4.18 Ns = 1.70 kg x Velocity

To find the velocity of the puck, we can rearrange the equation:

Velocity = 4.18 Ns / 1.70 kg

Calculating the velocity:

Velocity ≈ 2.46 m/s

So, the speed of the puck just after it leaves the hockey stick is approximately 2.46 m/s.