A block of mass 0.433kg is hung from a vertical spring and allow it to reach equilibrium rest. As a result the spring is stretched by 0.603m. Find the spring constant.

force= kx

.433*g=k(.603) solve for k in Newtons/meter

To find the spring constant, we need to use Hooke's Law, which states that the force exerted by a spring is directly proportional to its displacement from its equilibrium position.

Hooke's Law equation is given by:
F = -kx

Where:
F is the force applied to the spring (in Newtons),
k is the spring constant (in N/m),
x is the displacement of the spring from its equilibrium position (in meters).

In this case, we have the following information:
mass (m) = 0.433 kg
displacement (x) = 0.603 m

First, let's calculate the force (F) applied to the spring using the equation:

F = m * g
where g is the acceleration due to gravity and approximately equal to 9.8 m/s².

F = 0.433 kg * 9.8 m/s²
F = 4.2444 N

Now, we can solve for the spring constant (k) using Hooke's Law equation:

k = -F / x

k = -4.2444 N / 0.603 m
k ≈ -7.04 N/m

The negative sign indicates that the spring is acting in the opposite direction of the displacement.

Therefore, the spring constant (k) is approximately 7.04 N/m.