A candy sample is completely combusted in a bomb calorimeter. The calorimeter contains 982 g of water, and the measured temperature increase is 2.62°C. What is the fuel value of the candy sample in

nutritional Calories?

q = mass x specific heat x (Tfinal-Tinitial)

q = 982 g x 1 cal/g x 2.62 = approximately 2,572.8 calories (the real kind of calorie). I would round that to 2.57E1 kilocalories. Since the nutritional calorie (the so-called Big calorie) = 1 kcal, the answer is 2.57 Cal.

Well, if my calculations are not melted, we can find the fuel value of the candy sample by using the formula:

Fuel value = (mass of water) x (temperature increase)

So, plugging in the numbers, we get:

Fuel value = (982 g) x (2.62°C)

Now, to make things more exciting, let's convert grams to kilograms:

Fuel value = (0.982 kg) x (2.62°C)

And now, let's build some suspense by multiplying:

Fuel value = 2.57 kcal

Ta-da! The fuel value of the candy sample is 2.57 nutritional Calories. Just remember, this is for calculating purposes only, and eating a candy sample is not a recommended method for boosting your energy levels.

To determine the fuel value of the candy sample in nutritional calories, you can use the equation:

Fuel value (in nutritional calories) = q / m

Where:
- q is the heat absorbed by the water in the calorimeter, and
- m is the mass of the candy sample.

Given information:
- Mass of water (m) = 982 grams
- Temperature increase (∆T) = 2.62°C

However, we need additional information to calculate the heat absorbed by the water (q). Specifically, we need the specific heat capacity of water (c).

Please provide the specific heat capacity of water in units of cal/g°C or J/g°C.

To determine the fuel value of the candy sample in nutritional Calories, we need to calculate the heat energy released during combustion. This can be found using the equation:

Heat energy (in calories) = mass of water (in grams) x specific heat capacity of water (in calories/gram°C) x change in temperature (in °C)

First, convert the mass of water from grams to kilograms:
982 g ÷ 1000 = 0.982 kg

Next, convert the change in temperature from Celsius to Kelvin:
Change in temperature (in K) = change in temperature (in °C) + 273.15
Change in temperature (in K) = 2.62 + 273.15 = 275.77 K

The specific heat capacity of water is approximately 4.18 J/g°C.

Now, let's calculate the heat energy released in calories:
Heat energy (in calories) = 0.982 kg x 4.18 J/g°C x 275.77 K

To convert the heat energy from joules (J) to calories, we need to multiply it by the conversion factor:
1 calorie = 4.184 joules

Now, let's calculate the fuel value of the candy sample in nutritional Calories:
Fuel value (in calories) = Heat energy (in calories) ÷ 1,000

Finally, to convert calories to nutritional Calories, we divide by 1,000:
Fuel value (in nutritional Calories) = Fuel value (in calories) ÷ 1,000

By following these calculations, you can find the fuel value of the candy sample in nutritional Calories.