Am having trouble figuring out how to work this problem. We are currently studying about least common multiples.

The problem is: Stacey jogs every third day and swims every fourth day. If she is jogging on Monday, what day of the week will she end up jogging and swimming?

Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24

Multiples of 4: 4, 8, 12, 16, 20, 24

What is the smallest multiple of both 3 and 4?

12 is the answer

Wednesday

wedsday

Easy

Friday

12 days

To solve this problem, you need to find the least common multiple (LCM) of 3 and 4. The LCM is the smallest number that is divisible by both 3 and 4. Here's how you can find it:

1. Start by listing the multiples of each number until you find a common multiple.

Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, ...
Multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, ...

The first common multiple is 12.

2. Now, you need to determine the pattern of Stacey's jogging and swimming schedule. Since she jogs every third day and swims every fourth day, you'll find that the pattern repeats every 12 days.

3. Stacey starts jogging on Monday, which is day 1. To find out what day of the week she will end up jogging and swimming, divide the number of days by 7 (the number of days in a week) and find the remainder.

12 รท 7 = 1 remainder 5

Since there is a remainder of 5, count five days from Monday to find the day when Stacey will end up jogging and swimming. The answer is Saturday.

Therefore, Stacey will end up jogging and swimming on Saturday.