A crow is flying horizontally with a constant speed of 2.50 m/s when it releases a clam from its beak. The clam lands on the rocky beach 2.20 s later. Consider the moment just before the clam lands. (Neglect air resistance.)

A) What is its horizontal component of velocity?
B) What is its vertical component of velocity?

*Both in m/s

A) 2.5m/s

B) 9.8 * 2.2 = 21.56 m/s

how did you get 9.8

To find the horizontal and vertical components of the velocity of the clam just before it lands, we need to analyze the motion of the crow and the properties of projectile motion.

Given:
Horizontal speed of the crow (and clam) = 2.50 m/s
Time taken for the clam to land = 2.20 s

A) Horizontal component of velocity:

Since there is no air resistance and the crow is flying horizontally, the horizontal component of velocity does not change. It remains constant.

Therefore, the horizontal component of velocity of the clam just before it lands is also 2.50 m/s.

B) Vertical component of velocity:

To find the vertical component of velocity, we can use the equation of motion:

vf = vi + at

Where:
vf = final velocity
vi = initial velocity
a = acceleration (due to gravity, which is -9.8 m/s^2)
t = time

In this case, the initial vertical velocity of the clam is zero because it was released from the crow's beak. The final vertical velocity of the clam just before it lands is what we need to find.

Using the equation of motion, we have:

vf = vi + at
vf = 0 + (-9.8 m/s^2)(2.20 s)

vf = -21.56 m/s

Note that the negative sign indicates that the velocity is directed downwards.

Therefore, the vertical component of velocity of the clam just before it lands is approximately -21.56 m/s.

To find the horizontal and vertical components of velocity of the clam, we need to analyze the motion of the crow when it released the clam.

Let's break down the information given:
- The crow is flying horizontally with a constant speed of 2.50 m/s.
- The time it takes for the clam to land on the rocky beach is 2.20 seconds.

From these pieces of information, we can determine the initial horizontal velocity of the clam just before it was released from the crow's beak.

A) What is its horizontal component of velocity?

Since the crow is flying horizontally and drops the clam without any vertical motion, the horizontal component of velocity remains constant throughout. Therefore, the horizontal component of velocity of the clam just before it was released is 2.50 m/s.

B) What is its vertical component of velocity?

To determine the vertical component of velocity, we need to calculate the time it took for the clam to hit the ground after being released.

Given that the time it took for the clam to land on the beach is 2.20 seconds, we can use this time to find the vertical distance traveled by the clam.

The equation for vertical distance (d) is given by:
d = (1/2) * g * t^2

Where:
g is the acceleration due to gravity (9.8 m/s^2)
t is the time (2.20 s)

Using the values given, we can calculate the vertical distance traveled by the clam:
d = (1/2) * 9.8 * (2.20)^2
d ≈ 23.62 m

Now, we know the vertical distance traveled by the clam just before it lands is approximately 23.62 meters.

We can use this distance to find the vertical component of velocity (v) using the equation:
v = sqrt(2 * g * d)

Using the values given, we can substitute them into the equation to find the vertical component of velocity:
v = sqrt(2 * 9.8 * 23.62)
v ≈ 19.61 m/s

Therefore, the vertical component of velocity of the clam just before it was released is approximately 19.61 m/s.